Which is the valid broadcast ID for the IP address 126.96.36.199 with a subnet mask of 255.255.255.128?
188.8.131.52 is the valid broadcast ID for the IP address 184.108.40.206 with a subnet mask of 255.255.255.128. The valid range for the IP address 220.127.116.11 with a subnet mask of 255.255.255.128 is 18.104.22.168 – 22.214.171.124. The subnet ID is 126.96.36.199.
Subnetting allows you to split single and large subnets defined by Class A, B, and C IP addresses into multiple subnets with smaller IP address host ranges. Subnetting allows efficient use of IP addressing space, which has become a scarce resource.
To subnet an existing network, you will use host bits to split the IP address into multiple logical subnets. For example, if you use three bits of the host ID for subnetting, you have created 23 = 2 x 2 x 2 = 8 subnets. Remaining bits of the host ID in decimal form will form the number of hosts on each subnet.
All other options are incorrect as these IP addresses fall in other subnets.
188.8.131.52 is the network ID for the next subnet created when using a mask of 255.255.255.128 on the class C network 184.108.40.206. The following network IDs are created when you use a mask of 255.255.255.128 on the class C network 220.127.116.11:
– 18.104.22.168 – Valid range 22.214.171.124-126.96.36.199, 188.8.131.52 is the broadcast
– 184.108.40.206 – valid range 220.127.116.11-18.104.22.168, 22.214.171.124 is the broadcast
126.96.36.199 and 188.8.131.52 are both valid addresses in the second subnet created, that is, the 184.108.40.206 network.